wildcard question

[bozance]

Hello all,

I have the following that shows the player where they are when they enter a location:

$location.append("hall")

To do this, first I have to remove the previous location from displaying. Is there a way to say

$location.remove("x")

Where x denotes ANY value? For example, if you moved into the hall from the dining room or living room, "remove" would remove EITHER the dining room or living room from displaying.

[Aleema]

That's the actual code. Just doesn't take variables, I believe. $location.remove("hall")
What's your problem? Choosing whether to toggle off the dining room or the living room? That seems a logic problem for you, rather than a magic code for Python. When exiting a room, then you should remove it from the location, rather than try to retrospectively find out where you left from the next location.

Is there a reason you're not just doing: $location = "hall" ? Does the location variable really contain multiple values (are you in more than one place at once)?

[bozance]

I solved it. I just have to clear the variable with $location=[] and then append the new location. I realize this isn't how a list is supposed to be used, but I didn't want to have to create a new actual variable for every room. Not that this method saves that much space probably, but...

Anyway thanks Aleema.