Ren'py launch itself but with a different game directory?

[uyjulian]

Okay, so how do I launch ren'py from within ren'py?

For example, my directory...

./game/
./game1/
./game2/
./game3/
./lib/
./renpy/
./renpy.app/
./renpy.exe
./renpy.py
./renpy.sh
./log.txt

So, when renpy is launched, it selects the game folder by looking to folder named by executable (except for folder ”renpy”); if executable begin with space or underscore, the folder without; game; data; and launcher/game. (ln163 ./renpy/bootstrap.py)

So then ren'py launches game folder ./game/ since it is the first valid folder to be in the list.

The folder ./game/ contain a chooser to select ./game1/, ./game2/, or ./game3/。

How do I launch ren'py from ren'py itself but forcing a different game directory?

[PyTom]

Here's the code from the launcher with the launcher-isms cut out. It should be unindented a level, but I'm lazy and it's after midnight.

Code: Select all

    init python:
        import sys, os, subprocess 

        def launch(path):

            # Find the python executable to run.
            executable_path = os.path.dirname(sys.executable)

            if renpy.renpy.windows:
                extension = ".exe"
            else:
                extension = ""

            if persistent.windows_console:
                executables = [ "python" + extension ]
            else:
                executables = [ "pythonw" + extension ]

            executables.append(sys.executable)

            for i in executables:
                executable = os.path.join(executable_path, i)
                if os.path.exists(executable):
                    break
            else:
                raise Exception("Python interpreter not found: %r", executables)

            # Put together the basic command line.
            cmd = [ executable, "-EO", sys.argv[0], path ]

            # Launch the project.
            cmd = [ renpy.fsencode(i) for i in cmd ]

            subprocess.Popen(cmd)