Add a random image to a screen

[Keinart]

It is possible to add a random image to a menu screen? Basically I have a set of images and I want to use the Add function to display only ONE of them, randomly. So basically everytime the user opens that menu screen he will see a different image everytime.

[xela]

You have no idea how many answers to this question there are on this forum already...

[Keinart]

You have no idea how many answers to this question there are on this forum already...

I've been looking for it for a while and couldn't find it, would you mind giving a hand?

[xela]

http://lemmasoft.renai.us/forums/search ... background

Or try different searchwords...

[Keinart]

http://lemmasoft.renai.us/forums/search ... background

Or try different searchwords...

I've already did that, but none of the solutions there are working for me. I've already tried different things, the one that seems to work better is this one:

Code: Select all

    add renpy.random.choice(["imageone.png", "imagetwo.png", "imagethree.png"])

The issue is that I'm trying to do this in the preferences menu, and then when I change ANYTHING in the menu, let it be move the sound bar or change from window to full screen mode or anything like that, the image is changed again (in fact it changes a for every little movement I do in the sound bar for example, what is kinda funny). I need something that picks one imagen for the screen and keeps it until I leave the screen and come back again.

[xela]

How about:

Code: Select all

screen scr():
    default img = renpy.random.choice(["imageone.png", "imagetwo.png", "imagethree.png"])
    add img

?

[Keinart]

How about:

Code: Select all

screen scr():
    default img = renpy.random.choice(["imageone.png", "imagetwo.png", "imagethree.png"])
    add img

?

Ahh, it works. I knew I wasn't thinking correctly, I just had to put a new screen inside the screen, that makes sense. Thank you for the help!