Syntax Error with If statements

[maggert]

I'm having a hard time creating a random household generator for a tabletop campaign I'm running. It's giving a syntax error for line 76 in my code (if abandoned = 1:) seen as below:

Code: Select all

menu:
    "Choose a town."
    
    "Fortree City":
        $townname = "FortreeCity"
        $roommatepossible = 1
        $religionpossible = 1
        $typepokemon1 = "Bug"
        $typepokemon2 = "Flying"
        $typepokemon3 = "Grass"
        jump startgen
        
    "No idea.":
        "Yeah, I'm not sure, either."
        jump generic
        
label startgen:

$abandoned = renpy.random.randint(0, 1)

if abandoned = 1:
    #Pairing numbers: Dating 1, Engaged 2, Married 3, Not 4-6 #
    $paired = renpy.random.randint(1, 6)
    if paired >= 4:
        $ singlekids = renpy.random.randint(0, 1)
        if singlekids = 1:
            $ numbersinglekids = renpy.random.randint(1, 3)
        else:
            $ numbersinglekids = 0
    else:
        $ singlekids = 0

[PyTom]

Python uses = for assignment, == for comparison. So you'll want to write:

Code: Select all

if abandoned == 1: