Call screen accepting conditional arguments? (What's the best way to do this?)

[LeonDaydreamer]

Hey guys, I'm having an efficiency issue - in that my code would be a lot more efficient if I knew Python better :/
Can someone tell me what's the best way to put together a 'call screen' statement with conditional arguments?

Let's say a screen accepts multiple arguments, but depending on your progress in the story you would only be sending certain ones to it. So in my head, where things work with the power of magic and happiness, it looks like something like this:

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$ renpy.call (MYSCREEN, "arg1, arg2" + if abc (", arg3, arg4") + if xyz (", arg5, arg6"))

.... I'm sure it would need to be written with the arguments list as a string that gets interpreted by the call statement, in which certain arguments are added or omitted or something of the sort, but I have no idea what the proper way to execute that would be. Can anyone shed some light on this issue?

** Right now my solution is:

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if xyz:
   call screen MYSCREEN (arg1,arg2,arg3,arg4,arg5,arg6)
elif abc:
   call screen MYSCREEN (arg1,arg2,arg3,arg4)
else:
   call screen MYSCREEN (arg1,arg2)

And it's just not a very efficient way of handling this issue...

[Remix]

If you can build/manage a list, you can pass in that as parts of the *args special parameter... sample

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screen vari_args( *args ):
    vbox:
        area (0.8, 0.0, 0.2, 0.2)
        text "{0}".format( args )
        for arg in args:
            text "{0}".format( arg )

label start:
    # just a random list of [ 0, 1, 2 .... 7 ] for testing
    # refresh restart a few times
    $ args = [k for k in range( renpy.random.randint(3, 8) )]
    show screen vari_args( *args )
    "Words"