[Answered] generating random number with len(variable)

[Xasrai]

Hello. I'm wondering if it's possible to use random to generate a number that is within the confines of the length of a list?


What I'm trying to do is take the sum of 2 lists, then randomly choose one of the numbers from one of the lists to decrement by one, until the total of both lists is no longer above 10.

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#This code theoretically prevents exposure  and desire from being above 10 but only by removing from exposure. 


$ i = 0
while (sum(desire_list) + sum(exposure_list)) > 10:
    $k = renpy.random.randint(0,9)
    if exposure_list[k] > 0:
	    $exposure_list[k] -=1

$ i += 1 

What I WANT is to be able to define random like this:

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    $k = renpy.random.randint(0,[len(exposure_list)])

so that no matter how many variables get added to the exposure list, the game will always roll within the value of the list. It's not REALLY important, as I can just update the second number to reflect the total length of list as a final part of creating the game, but if I forget, this could throw an infinite loop, if >10 were allocated to exposure_list in an index higher than 9.

[Ocelot]

What is wrong with $k = renpy.random.randint(0, len(exposure_list) - 1) ?

[Remix]

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$ i = 0
while sum( desire_list + exposure_list ) > 10:
    item = renpy.random.choice( desire_list + exposure_list )
    item = max( 0, item - 1 )
$ i += 1

Theoretically should work, presuming I read what you want properly

[Xasrai]

What is wrong with $k = renpy.random.randint(0, len(exposure_list) - 1) ?

Absolutely nothing at all. I was apparently just screwing up with my syntax.

Thanks for your help!