[solved]how can I calculate xalign using xpos and xsize?

[Kia]

as you know the "xanchor" changes with "xalign", this made me wonder what's the correct formula for calculating "xalign" of a dragged child using available information:
drag[0].x
drag[0].w
and config.screen_width

[DragoonHP]

Code: Select all

cal_xalign_value = drag[0].x/config.screen_width

This should give you an xalign value in respect to the entire screen.

[Kia]

Code: Select all

cal_xalign_value = drag[0].x/config.screen_width

This should give you an xalign value in respect to the entire screen.

unfortunately this doesn't take into account the width of the drag's child and the change in the xanchor when drag is moved towards the left side of screen. only works if the width of child is zero.

[DragoonHP]

Can you tell me what you are trying to do? I'm not sure how width of a child affects xalign

[Per K Grok]

what's the correct formula for calculating "xalign" of a dragged child using available information:

I think this should work

xalign = xpos / (screenwidth - xsize)

[Kia]

I think this should work

xalign = xpos / (screenwidth - xsize)

thank you ^_^
it's was as simple as putting two and two together, yet I failed to see it for hours of trial and error.

[Kia]

Can you tell me what you are trying to do? I'm not sure how width of a child affects xalign

while using xalign, it's necessary that the anchor point of the child to be aligned along the child's width. for example:
xalign 1.0 causes the xanchor to be set to 1.0 and the child to be aligned by it's right side instead of the usual left side.
and xalign 0.5 sets xanchor to 0.5 and align the child by it's center to keep the object at the center.
that's why we have to consider the child's width in calculation, DragoonHP gave me the solution.