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How to make the first line of a menu dynamic?
Posted: Tue Jul 09, 2019 11:16 am
by jacob_ax
Hi everyone,
I'm trying to make something like this:
Code: Select all
define bman = Character("Bartender")
$ number = renpy.random.randint(1,3)
menu ask_for_a_drink:
#First we have three condition that will decide what will appear in the textbox (the bartender is talking)
if number == 1:
bman "What's your poison?"
if number == 2:
bman "You thirsty?"
if number == 3:
bman "What would you like today?"
#Then the choices that will appear on the menu screen
"Vodka":
some text and actions...
"Jin":
some text and actions...
"Wine":
some text and actions...
the problem is, this doesn't work. Is there a way to deal with this?
Thanks
Re: How to make the first line of a menu dynamic?
Posted: Tue Jul 09, 2019 11:54 am
by DannX
You could try this:
Code: Select all
# A list with possible greetings for the bartender
$ bman_texts = ["What's your poison?", "You thirsty?", "What would you like today?"]
# pick one of them with renpy.random.choice and store it in a variable called t
$ t = renpy.random.choice(bman_texts)
menu ask_for_a_drink:
bman "[t]" #have bman character speak the selected text
"Vodka":
# some text and actions
pass
"Jin":
# some text and actions
pass
"Wine":
# some text and actions
pass
With renpy.random.choice, the game randomly selects one element from a list, in this case, one string of text. Then you interpolate it with [] in renpy dialogue. This saves typing since you don't need randint and a lot of if statements.
Re: How to make the first line of a menu dynamic?
Posted: Tue Jul 09, 2019 12:00 pm
by jacob_ax
Thanks!!!
