How do I get a integer from FilePageNameInputValue?

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How do I get a integer from FilePageNameInputValue?

#1 Post by nillan3 » Sat Jan 25, 2020 3:37 pm

In screen.rpy under the

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screen file_slots(title):
tab there is a line that says

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default page_name_value = FilePageNameInputValue(pattern=_("Page {}"), auto=_("Automatic saves"), quick=_("Quick saves"))
and to get the number from FilePageNameInputValue you have to do

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value page_name_value
However, I'm trying to get the value out as an integer. I know there is [page], but that doesn't update when you press the textbutton

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textbutton _(">") action FilePageNext()
I'm thankful for any help I can get!

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Re: How do I get a integer from FilePageNameInputValue?

#2 Post by gas » Sat Jan 25, 2020 8:21 pm

Returns the current file page as a string.

So, probably

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$ page_num=int(FileCurrentPage())
But beware that this turn a bit messy if you're in the "quick" or "auto" page.
10 ? "RENPY"
20 GOTO 10


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