Lemma Soft Forums

Posted: **Wed Jan 03, 2024 4:22 am**

I want to make the label name a variable.
It's screens.py

screen menu():

    textbutton _("Ticket001") action Show("choice_ticket", character="gacha001")
    textbutton _("Ticket002") action Show("choice_ticket", character="gacha002")


screen choice_ticket(character):

    zorder 100
    textbutton _("GET") action Start("[character!tq]")

And it's script.py

Code: Select all

label gacha001:

    "get 001!"

return

label gacha002:

   "get 002!"

return

I expected it.
When you press the GET button on the Ticket001 screen, you are connected to gacha001.
When you press the GET button on the Ticket002 screen, you are connected to gacha002.

But I saw an error.

Code: Select all

ScriptError: could not find label '[character!tq]'.

Could I use the name of the label as a variable?
Please help me.

============

I solved it! thank you!

Code: Select all

screen choice_ticket(character):

    zorder 100
    textbutton _("GET") action Start(character)

Lemma Soft Forums

(solved)I want to make the label name a variable

(solved)I want to make the label name a variable